Question

3) Starting from rest, a drill bit reaches 24Ort radians per second in 3.0s. a) How many revolutions does it make during this time? b) Consider a point on the edge of the drill bit. Sketch a graph of angular position vs. time for this point. c) Sketch a graph of angular velocity vs. time for this points d) Sketch a graph of angular acceleration vs. time for this point.

Answer 1

Date: Page No.: - Aus31 W = 240 rad/ sec. Wo= 0, time, t = 38. . Angular acceleration , L= W-Wo = 240 TT rad - 3 3² 2= 80 Ti rad/a AO = 0-0 = wott I at O = Oot Wot t I xat O= 0 + 0x3 + 1 (807) 3² radians 2 0=3607 radians. 180 .. no. of revolutions - 0 = 360 71 27 ZX = 180 Angular position of point on edge given as O= Wotti x +² of drill bit is. But Woro? 0 = 1 (807) t no (radians) 360 TT time (s)

@ Angulas velocity of this particle is given as a wa do = √ 2 d (t = 12.2 t = at W =(805) + A WC rad/sec) 19(805) t 24000 | of t=3$ 7 time (s) ular acceleration is uniform which is givenas - 1 2 = 8ota A2 (rad/sec2) 800 time(s)