Question

Car on curve 12 3 4 5 67 A car is traveling around a horizontal circular track with radius r = 240 m at a constant speed v angle 8A 29 above the x axis, and the angle Op 58 below the x axis. 25 m/s as shown. The 1) What is the magnitude of the car's acceleration? m/s Submit 2) What is the x component of the car's acceleration when it is at point A m/ st Submit 3) What is the y component of the car's acceleration when it is at point A sSubmit

Answer 1

1)

acceleration = v²/r = (25)²/(240) = 2.60 m/s²

2)

x component of acceleration is

a_x = (2.60)*(cos 29) = 2.27 m/s² (In the negative x direction)

3)

y component of acceleration is

a_y = 2.60*(sin 29) = 1.26 m/s²

4)

x component = (2.60)(cos 58) = 1.37 m/s² (In the negative x direction )

5)

y component = (2.60)(sin 58) = 2.20 m/s²

6)

As the car passes the point B, the angle $\theta$ _b decreases, and sin $\theta$ _b decreases.

So, the y-component of acceleration ( a sin $\theta$ _b) decreases.