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11. You have a mixture of 0.10M HCl and 0.10M HI. What is the pH of the resulting solution? a. 1.00 b. 2.00 C. 0.70 d. 0.20 e
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# ASPH is ove log of fit conc ab AS PH - – log [H+ Now we have Oolom HCL 2 0.10 M H I so [ Ht] Conc = 0.20 M PH= – log [0.20please don't forget to press thumbs up thanks for posting questions

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