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Example 7. A current of 1 μΑ is generated by light striking a phototube. If this current is made to flow through a 1 MJ2 resistor, what is the voltage across the resistor?

Phototube 1 Meg 180 V

Example 8. What are the values of i, i2, i, and i4 in the circuit shown below? Kirchhoffs current law applied to the two junctions gives the following information. The currents can be calculated if ii and i2 are determined, which can be calculated with the value of the battery voltage, which is 12 V, and the resistances Ri-1.2 K2, and R2 2.4 K

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Answer #1

Voltage(V) across resistance( R)

V=iR

i is current flowing through resistance.

(1)Kirchhoff's current law-

Sum of all current at any junction =0

(2) Kirchhoff's voltage law-

Sum of voltage of closed loop(circuit) is =0

3 - Ixio3 The Noltage across the im Resis+anc«- 1lmv Ar, 3 2 в 4-1 Apply kCL:- at (l) 丁unction (A)!- 3 72 (2Apply KNL 12 3 2. 2) In mesh(2) R2 24 X13 12-5X10-3 A om enuation (L)

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