Homework Answers
Using Snell's law
n1*sin(theta1) = n2*sin(theta2)
1.33*sin(54.3) = 1.52*sin(theta2)
sin(theta2) = 1.33*0.81208353/1.52 = 0.71057
Theta2 = 45.25 degree in oil
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How
do I solve?
A light ray in air hits a piece of quartz at a 39.0 deg angle. Inside the quartz, the light slows down to 2.06 1048 m/s. At what angle does the light travel in the quartz? (Hint: find n.) (Water n 1.33, Air n 1.00) (Unit- deg) 003-20і9Acelha Corporation. All Rights Reserved.
A light ray in air (n= 1) is incident on a thin film of oil (noil = 1.60) floating on top of water (nwater = 1.33), as shown below. The wavelength of the incident light in air is Aair = 640 nm. The oil layer has a thickness t = 0.5 um. The ray is assumed to be incident practically along the normal. That is, we won't be worried about angles of reflection or refraction when doing this problem. However,...
please show work
the ray of light in air hits the surface of water (n=1.33) at an angle of 23° what is the angle of the light in 2) Light goes from glass (n-1.5) to plastic (n-1.4). What is the critical angle for total internal reflection? 3) If light travels in glass (n-1.5) which is surrounded by air (n- 1) and hits the glass/air surface at an angle of 44, does it go into the air? If so, what is...
2. Suppose a ray of light travels from air (n 1.00) into water (n 1.33). Use Snell's law to calculate the refraction angle in the water if (a) the ray is perpendicular to the surface of the water, and (b) if the angle of incidence is 30°. Sketch both cases.
1.33 1. Light travels from glass to water. It strikes the boundary at an angle of 45 degrees. At what angle is the refracted ray in the water? Tour dot snell's Law = n, sing, = n₂sina O a= na sinde Az = 1 o sin45 - 12 The mount Port nge. The e an
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