Question

What is the force on the charge located at x = 8.000 cm in the figure given that q = 1.850 pC ? The other two charges are located at 3.000 cm and 11.00 cm. Take the positive direction as pointing to the right. -2q tq +9 10.00 x (cm) 5.000 0 force

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Answer #1

From the information in the question..

Using the concept of coloumbs square law we can we can determine the force on each side( left and right ) as we know the formula which should be used is

F=KQq/r²

Where k=9*10^9 (constant)

Suven other two ehouges (Hom dinaham) are Located at r,- 3 cm 0.03ญา using force due to etll be duredtel owauds-ve x axis 2 (8-3) -5cm o-03)2 using the cencepk Co o3) 68.45 N 2 wet forre C0.05% let) 68-45-24-642 Co o5)2 -24-642 N As t tepreaent -ve beraur ot it acts n -Vex axts foce due to gh w be duueche!

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