Question

What is the force on the charge located at x 16.00 cm in the figure given that q 1.650 HC? The other two charges are located at 6.000 cm and 22.00 cm. Take the positive direction as pointing to the right. +4 -2q +g 0.00 20.00 (em) force:
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Answer #1

here i am using a formula to calculate the force acting on the charge located at 16 cm due to individual charges is F = kqQ/r^2 and then i added both forces to get net force using

斤 0 χι 12 ?6 내꺼 F 13.6 N 2

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