Question

Physics prnd by What is the force on the other two charges are lo right located at x-16.00 in the figure below given that q-2.450 pC? The at 6.000 and 22.00m. Take the positive direction as pointing to the -2q 10.00 20.00 cm O Previous ⓧ Give Up & View Solution ⓢGive up & View Solution、Check Answer 0Next aeit D Check Answer 0 Next Exit

Answer 1

Force on the Charge = -2q*E

Electric Field at that point due to two other charges is,

E = k*q/r1^2 - k*q/r2^2
E = k*q* [1/r1^2 - 1/r2^]
E = 8.9*2.450*10^3 * [1/(10/100)^2 - 1/(6/100)^2]
E = - 3.87 * 10^6 N/C

F = -2q*E
F = - 2*2.450 * 10^-6 * (- 3.87 * 10^6 ) N
F = 18.96 N