Question

16. Using the following information, calculate the sublimation of S(s) to S(g) Mg(s) S(s) MgS(s) AHo 343 kJ/mol Mg(s) Mg(g) Mg(g) Mg (g) 2e S(s)> S(g) 2e > S2(g) Mg2 (g) S2g) -> MgS(s) A) 279 kJ/mol B) 575 kJ/mol C) 1179 kJ/mol D) 965 kJ/mol E) 4651 kJ/mol AHo 148 kJ/mol 2+ AH° 2186 kJ/mol ΔΗ S(g) AHo 450 kJ/mol AHo3406 kJ/mol _

Answer 1

mg esot Scs) + Mg SCCO SHE-363 kJ/mol ng (S) - mg (g) AH = +148 kJ/mol mgcg) mg 2(g) + 2e r = 2186 kJ / mo ! Seg) +265 (g. H - 450 KIlmo) might 5² (g) mgsco H = -3306 kJ mol To find sublimation of Sco) to sig) we need to use Hess's law here & do the respective rearrangement. For this keep equation © as it is and reverse the equation D and

Mg(s) + Scs) mg Scs) AH = -343 kJ/mol Mgcg) mgcs) H = -148 kJ/mol Myag+2e -> Mg Cg) SHO: - 2186 kJ/mol Sig Scg) +200 SH = - 450kJ/mol Mg Scs) - Mg²tg) + 5²(g) SH² 3 406 kJ/mol Now by adding sto for all reaction & Cancelling all other terms to get Scs) Seg). Mgest + Scs) + Mgsts) OH-343kJ/mol mgg) -> Does) DHS-18 Kuimol mg ug)+2smag) OHº5-2-486 kJ/mol 29 --S9+ 2e 44°= - 450 kJ/mol ragingses) ng g +8g, Jr1=3406 kJ/mo) Tscs) Scg) AH = 279 kJ/mol Therefore sublimation energy for conversion of Scs) to Seg) is 2.79 kJ/mol.

If you find any mistake please mention in the comment box.

Thanks.