Question

a Consider the balanced chemical equation 4Cr(s) + 302(g) + 2Cr2O3(s) What mole ratio would you use to calculate how many moles of oxygen gas would be needed to react completely with a given number of moles of chromium metal? 4 mol O2 3 mol Cr 2 mol O2 3 mol Cr 3 mol O2 2 mol Cr 3 mol O2 4 mol Cr b Consider the balanced chemical equation 4Cr(s) + 302 (9) + 2Cr2O3(s) What mole ratio would you use to calculate the number of moles of product that would be expected if a given number of moles of chromium metal reacts completely? 4 mol Cr,03 2 mol Cr 3 mol Cr2O3 2 mol Cr 2 mol Cr2O3 4 mol Cr 2 mol Cr2O3 3 mol Cr

Answer 1

u Crisi + 30 (9) 2 Cr, O₂ (si of 4 mal Cr this , 3 mol of Or will be needed 4 mol Cr = 3 mol O2 3 mol O2 4 mol Cr d option 3 my o₂ 4mor Cr 4 Cr (61 + 30 (9) - 2 Cr, Og (s u mol of Cr would produce 2 mol of Cr Og this 4 mol Cr= 2 mol Cry Og 2 mol Cr Og 4 mol C 2 mol Cr, og 4 mol Cr option