A bicyclist is finishing his repair of a flat tire when a friend rides by at 3.4 m/s. Two seconds later, the bicyclist hops on his bike and accelerates at 2.8 m/s2 until he catches his friend.
I have gotten to 0 = 1.4t^2 - 3.4t - 6.8 and used the quadratic equation, but it gives me the incorrect answer.
the correct answer is 3.73 i have answered my own question
A bicyclist is finishing his repair of a flat tire when a friend rides by at...
A bicyclist is finishing his repair of a flat tire when a friend rides by at 3.4 m/s. Two seconds later, the bicyclist hops on his bike and accelerates at 2.8 m/s2 until he catches his friend. time that he takes to catch his friend is 3.73s (=t) how far has he traveled in this time? What is the velocity at this time?
A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.1 m/s . Two seconds later the bicyclist hops on his bike and accelerates at 2.4 m/s2 until he catches his friend. a) How much time does it take until he catches his friend (after his friend passes him)? Express your answer using two significant figures.
A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.2 m/s . Two seconds later the bicyclist hops on his bike and accelerates at 2.6 m/s2 until he catches his friend. A.) How much time does it take until he catches his friend (after his friend passes him)? B.) How far has he traveled in this time? C.) What is his speed when he catches up?
A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.1 m/s . Two seconds later the bicyclist hops on his bike and accelerates at 2.5 m/s^2 until he catches his friend. (a) How much time does it take until he catches his friend (after his friend passes him)? (b) How far has he traveled in this time? (c) What is his speed when he catches up?