1)
At equilibrium:
Mg3(PO4)2 <----> 3 Mg2+ + 2 PO43-
3s 2s
Ksp = [Mg2+]^3[PO43-]^2
1.04*10^-24=(3s)^3*(2s)^2
1.04*10^-24= 108(s)^5
s = 6.262*10^-6 M
Answer: 6.26*10^-6 M
Only 1 question at a time please
1. Determine the solubility of Mg3(PO4)2 given that Ksp = 1.04 x 1044. KNO, 0.0005 0.001...
1. Determine the solubility of Mg3(PO4)2 given that Ksp = 1.04 x 1044. KNO, 0.0005 0.001 0.0015 0.0025 0.003 0.0035 0.004 0.002 1/T (K4) 2. The preceding graph shows data for the solubility of KNO3. Determine AG for ti dissolution of KNO3 using this data.
Calculate the molar solubility of Mg3(PO4)2 Ksp = 1 X 10-24
Determine the area under the standard normal curve that lies to the right of a(Z) = -0.42, b(Z) =0.54, c(Z) = - 0.76, and d(Z) = -1.91 MyStatLab Data Set - Google Chrome statcrunch.com/app/?dlim=comma&ft=false&dataurl=https%3a%2f%2fxlitemprod.pearsoncmg.com%2fGetPlayerFile.ashx%3fguid%3d1e9f4376-4819-4d55-8ca0-c41ee702bb63 MyStatLab Data Set StatCrunch Applets Edit Data | StatGraph | Help Row vari vari var2 var12 var13 var14 ve -3.4 -3.3 -3.2 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 HNMONOFHHHHHNNNNNNNNNN -2.2 -2.1 -2 -1.9 0.0003 0.0005 0.0007 0.001 0.0013 0.0019 0.0026 0.0035 0.0047 0.0062 0.0082 0.0107...