Question

Determine the area under the standard normal curve that lies to the right of a(Z) = -0.42, b(Z) =0.54, c(Z) = - 0.76, and d(Z) = -1.91

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Answer #1

Solution,

Using standard normal table,  

a) P(Z > -0.42)

= 1 - P( Z < -0.42)

= 1 - 0.3372

= 0.6628

b) P(Z > 0.54)

= 1 - P( Z < 0.54)

= 1 - 0.7054

= 0.2946

c) P(Z > -0.76)

= 1 - P( Z < -0.76)

= 1 - 0.2236

= 0.7764

d) P(Z > -1.91)

= 1 - P( Z < -1.91)

= 1 - 0.0281

= 0.0.9719

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