Question

Are 0 0.66 0.07 .08 0.00 0.01 0.09 0.02 0.0003 0.0005 0.0007 0.0010 0.0013 0.0019 0.0026 0.0035 0.0003 0.0005 0.0007 0.0009 0.0013 0.0018 0.0025 0.0034 0.0045 0.0060 0.0080 0.0104 0.01.36 0.0174 0.0003 0.0005 0.0006 0.0009 0.0013 0.0018 0.0024 0.0033 0.0044 Standard Normal Distribution 0.03 0.04 0.05 0.0003 0.0003 0.0003 0.0004 0.0004 0.0004 0.0006 0.0006 0.0006 0.0009 0.0008 0.0008 0.0012 0.0012 0.0011 0.0017 0.0016 0.0016 0.0023 0.0023 0.0022 0.0032 0.0031 0.0030 0.0043 0.0041 0.0040 0.0057 0.0055 0.0054 0.0075 0.0073 0.0071 0.0094 0.0096 0.0099 0.0129 0.0125 0.0122 0.0166 0.0162 0.0158 0.0003 0.0004 0.0006 0.0008 0.0011 0.0015 0.0021 0.0029 0.0039 0.0052 0.0069 0.0091 0.0119 0.0154 0.0003 0.0004 0.0005 0.0008 0.0011 0.0015 0.0021 0.0028 0.0038 0.0051 0.0068 0.0089 0.0116 0.0150 0.0003 0.0004 0.0005 0.0007 0.0010 0.0014 0.0020 0.0027 0.0037 0.0049 0.0066 0.0087 0.0113 0.0146 0.0002 0.0003 0.0005 0.0007 0.0010 0.0014 0,0019 0.0026 0.0036 0.0048 0.0064 0.0084 0.0110 0.0143 0.0047 0.0062 0.0059 0.0078 0.0082 0.0102 0.0132 0.0107 0.0139 0.0179 0.0170

Answer 1

Date that television Given that : n= 1003 X = No. of person who indicate are a luxtary = 535 P = X - 535 -0.533 @ 1003 os it. So I can Can you provide provide options for you exact answers The sample is simple random sample, the value of np is 535 which is greater than 10. 95% C.L. c. I = For p ? Į tai Þ (1-6) = 0.533 ± 1.96 0.533 ×(1-0-533) 1003 C0.502, 0.564) we are 95% confident the proportion of adults in the country who belive that television are a luxury they could do without is between 0.502 and 0.564.

Date It is not likely that a supermajority of adults in the country believe that television is luxuro they could do without because the 95%. c. 1. does not contain 0.6 95% c. 1. FOC (1-P) C-1 = CIÊh & 720 (1-P) ? = (1-0-533) I 1.96 (1-0-533) *0.533 1003 (0.436 0.498)