What is the ClO- concentration of a mixture that is 0.300 M in HF and 0.100 M in HClO.
HF Ka= 6.8*10-4
HClO Ka= 2.9*10-8
What is the ClO- concentration of a mixture that is 0.300 M in HF and 0.100...
What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.100 mol of NaOH were added?
Find the pH of a mixture that is 0.150 M HF and 0.10 M HClO. Ka = 3.5 x 10^-4.
Consider the titration of 25.0 mL of 0.100 M HF with 0.125 M KOH. The Ka is 6.8 x 10-4 for HF. What is the pH after 20.0 mL of base are added? Please show steps.
Calculate the pH for both a 0.100 M solution of HClO4 and a 0.100 M solution of a HClO (Ka = 2.9 × 10–8)? (Don't forget significant figures!)
What is the pH of a 0.100 M F- solution? ka(HF) = 6.8*10^-4 kb(F-) = 1.5*10^-11
(a) What is the pH of a solution that contains 0.100 M HClO and 0.300 M KClO? (b) If 50.00 mL of 0.100 M HCl is added to 1.00 L of the above buffer, what is the new pH? (b) If 50.00 mL of 0.100 M HCl is added to 1.00 L of the above buffer, what is the new pH?
5) Of the following acids, ________ is a strong acid. A) HNO2 B) H2CO3 C) HNO3 D) HClO 6) Calculate the hydrogen ion concentration in a solution of iced tea with lemon having a pH of 2.87. A) 2.9 x 10–2 M C) 1.3 x 10–3 M 7) Which one of the following is the weakest acid? A) HF (Ka = 6.8 × 10-4) B) HClO (Ka = 3.0 × 10-8) C) HNO2 (Ka = 4.5 × 10-4) D) HCN...
What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.030 mol of HCl were added?
Calculate the pH of a solution that is 0.100 M in hydrofluoric acid (HF) and 0.100 M in sodium fluoride (NaF). Ka of hydrofluoric acid is 6.3 x 10-4
7) Which one of the following is the weakest acid? A) HF (Ka = 6.8 × 10-4) B) HClO (Ka = 3.0 × 10-8) C) HNO2 (Ka = 4.5 × 10-4) D) HCN (Ka = 4.9 × 10-10) B) 5.7 x 10–2 M D) 2.9 x 10–3 M 22) Calculate the hydrogen ion concentration in a solution of iced tea with lemon having a pH of 2.87. A) 2.9x10–2M D) 2.9x10–3M B) 5.7 x 10–2 M E) 5.7 x 10–4...