What is the pH of a 0.100 M F- solution?
ka(HF) = 6.8*10^-4
kb(F-) = 1.5*10^-11
What is the pH of a 0.100 M F- solution? ka(HF) = 6.8*10^-4 kb(F-) = 1.5*10^-11
a)What is the kb for F- given that the ka for HF is 6.8*10-4. b)What is the pH of a 0.379 M solution of NaF? i just really need part b. i have part a.
What is the pH of a 0.400 M. solution of HF (Ka = 6.8 x 10-4)?
Find the pH and percent ionization for each HF solution. (Ka for HF is 6.8 x10-4.) Please use this Ka that is given to solve a. 0.250 M HF b. 0.100 M HF c. 0.050 M HF
Determine the pH of a solution that is 1.00 L of 0.100 M HF and 0.100 M NaF after 0.50 mole of solid KOH has been added to the solution. Ka(HF) = 3.5×10-4
Find the pH and percent ionization of each HF solution (Ka for HF is 6.8 X 10^-4) Please show your work, and explain. Thank you! Co < CHE180 Review Exercise 16.77 Find the pH and percent ionization of each HF solution (Ka for HF is 6.8 x 104) PartA Find the pH of a 0.240 M solution. Express your answer to two decimal places. pH Submit Previous Answers Request Answer X Incorrect; One attempt remaining: Try Agairn Part B Find...
Determine the pH of 1.33 M LiF. For HF, Ka is 6.8 x 10^-4.
If a solution of HF (Ka=6.8×10^−4) has a pH of 3.50, calculate the concentration of hydrofluoric acid. So far, I've made 5 incorrect attempts at the answer and have one attempt remaining. My answers were as follows: 0.00015, 1.5x10^-4, 1.5x10^-5, 0.001, and 0.00032 (This last answer prompted the website to tell me: "This value is the concentration of H+. This concentration and the Ka value can be used along with the equation for Ka to determine the initial concentration of...
Calculate the pH of a solution that is 0.100 M in hydrofluoric acid (HF) and 0.100 M in sodium fluoride (NaF). Ka of hydrofluoric acid is 6.3 x 10-4
Consider the titration of 25.0 mL of 0.100 M HF with 0.125 M KOH. The Ka is 6.8 x 10-4 for HF. What is the pH after 20.0 mL of base are added? Please show steps.
9. HF has a Ka = 6.8*10". Find the pH of a 0.15M solution of its % - ionization. HF and