Question

3. Complete and balance the following equation as written using the Method of Half-Reactions. Show your steps in a neat, organized manner Ci - CH + cios (in basic solution) combina fp 12-Rxn Reduced 1-Rxn Oxidized Ch 01 ch > clož Cl₂ 201 Cl2 20103 Cl₂the- 7201- clzt 6H₂O -> 20103 +124* 5/c/z the -> 2017 ao 5cl₂tle lock 2005 *12H? scz +10e -> 1001-2005 +124* > Cl₂ +6060 Flore. Clat6 H₂O + 106- 12H4+2 (10% +501 Ch +6 hot loct 2000zt2H+ - Cl2 +6720 +10e- +1204- 124* + 204- +26105 +5012 -> (12+6H20 +locl +1204-a 1240 +2c102 +5c2-7c/z+ 6H2O + loct + 1204 herk H:24 0:18 V 0:18 cl:12 1:12 22 - x - 2K +12014- Hj 24 dexo overall egn: 121 120 +2610,75cytetyt6H20 +10cl" + 2011 6048 + 3Cl2 > 501-+(103 + + 3 H2O

Answer 1

Increase en oxidatëtu munebes (ON)Khown as Oxiclatée. Deenase en Oan és Kuecenas rechichess Oxidation helkreactement . Cl2 +6+20 Hour 2003 +12H+ +10€ =D OCNEO O·N=ts Reduction fa naclemi__ Chtze zce. ON=O O.N=-f Meutêply by 5 and add to Cl2 + 6H2O 2010 + 12 47 loe Scl2 + 10 - > 40cc 66b2+ 6H20 > 20603+ADCEU2H+ Add 12 of both sedes 60/2 + 6H20+120 2010z +10 cē+12H+1204- 6cb2 + 6H2O +1201 S zclaz + docēt 121620 tch + 120H 72clos +10CLE6420