The above question completely based on Depreciation method ( SLM - Straight Line Method , DDB - Double Declining Method - 2/n year = 2/8 =0.25 = 25% depreciation rate .
We need to calculate year to shift depreciation between DDB to SLM with help of VDB( Variable Declining Method) - detail formula updated in Excel
Complete Analysis on Depreciation | |
Cost of a newly acquired Trotec($) | 2,00,000 |
Productive Life( Yrs) | 8 |
Salvage value | - |
Depreciation calculation @ DDB Method | |
Depreciation calculation @SL Method | |
Depreciation Rate | 10% |
Depreciation Straight Line Method | |
Cost of a newly acquired Trotec($)(a) | 2,00,000 |
Salvage value(b) | - |
Balance Value(a-b)- (c)-$ | 2,00,000 |
Productive Life( Yrs) (d) | 8 |
Depreciation Per Year ( c/d)-$ | 25,000 |
Normally Double Declining Method | |
of Depreciation ( 2times of Straight Line depreciation)-2/N
( N = No of Year)' so rate of depreciation |
25% |
Double Declining Method) | DDB to SL | |||||||||||||
Year | SLM ( Straight Line Method)$(f) | Book Value ($)(e) | Formula | Opening Balance($)(a) | Depreciation($)(b) | Closing Balance($)(c) | Formula | Book Value($)(g) | Depreciation($)(h) | Depreciation(VDB) | Depreciaton in $ | Book Value | ||
0 | 2,00,000 | Depreciation | Book Value | 2,00,000 | Depreciation(25%) ( as above) | Book Value | 2,00,000 | |||||||
1 | 25,000 | 1,75,000 | As per above | (e-f) | 50,000 | 1,50,000 | (a*b)= c | (a-c) | 1,50,000 | 50,000 | VDB(Cost of the asset,Salavage Value,Number of years,Year 0, Year1,2) | VDB(200,000,0,8Year,year 0,Year 1,2) | (g-h) | |
2 | 25,000 | 1,50,000 | (e-f) | 1,50,000 | 37,500 | 1,12,500 | (a*b)= c | (a-c) | 1,12,500 | 37,500 | VDB(200,000,0,8Year,year 1,Year 2,2) | (g-h) | ||
3 | 25,000 | 1,25,000 | (e-f) | 1,12,500 | 28,125 | 84,375 | (a*b)= c | (a-c) | 84,375 | 28,125 | VDB(200,000,0,8Year,year 2,Year 3,2) | (g-h) | ||
4 | 25,000 | 1,00,000 | (e-f) | 84,375 | 21,094 | 63,281 | (a*b)= c | (a-c) | 63,281 | 21,094 | VDB(200,000,0,8Year,year 3,Year 4,2) | (g-h) | ||
5 | 25,000 | 75,000 | (e-f) | 63,281 | 15,820 | 47,461 | (a*b)= c | (a-c) | 47,461 | 15,820 | VDB(200,000,0,8Year,year 4,Year 5,2) | (g-h) | ||
6 | 25,000 | 50,000 | (e-f) | 47,461 | 11,865 | 35,596 | (a*b)= c | (a-c) | 31,641 | 15,820 | VDB(200,000,0,8Year,year 5,Year 6,2) | (g-h) | ||
7 | 25,000 | 25,000 | (e-f) | 35,596 | 8,899 | 26,697 | (a*b)= c | (a-c) | 15,820 | 15,820 | VDB(200,000,0,8Year,year 6,Year 7,2) | (g-h) | ||
8 | 25,000 | - | (e-f) | 26,697 | 6,674 | 20,023 | (a*b)= c | (a-c) | - | 15,820 | VDB(200,000,0,8Year,year 7,Year 8,2) | (g-h) |
Derived PV on the basis of depreciation calculate above ( VDB basis) and we noticed that Present value after switch is $ 537637 which is higher by SLM ( without Switch ) - $ 2,00,000
So Switch is Acceptable
DDB to SL | Present Value | Present Value - Formula use | PV in $ term | |||||||||
Year | SLM ( Straight Line Method)$(f) | Book Value ($)(e) | Formula | Book Value($)(g) | Depreciation($)(h) | Depreciation(VDB) | Depreciaton in $ | Book Value | Depreciation on VDB Basis | |||
0 | 2,00,000 | Depreciation | Book Value | 2,00,000 | ||||||||
1 | 25,000 | 1,75,000 | As per above | (e-f) | 1,50,000 | 50,000 | VDB(Cost of the asset,Salavage Value,Number of years,Year 0, Year1,2) | VDB(200,000,0,8Year,year 0,Year 1,2) | (g-h) | $45,455 | PV(10%,Year1,-VDB base depreciation) | PV(10%,1,-50000) |
2 | 25,000 | 1,50,000 | (e-f) | 1,12,500 | 37,500 | VDB(200,000,0,8Year,year 1,Year 2,2) | (g-h) | $65,083 | PV(10%,Year2,-VDB base depreciation) | PV(10%,2,-37500) | ||
3 | 25,000 | 1,25,000 | (e-f) | 84,375 | 28,125 | VDB(200,000,0,8Year,year 2,Year 3,2) | (g-h) | $69,943 | PV(10%,Year2,-VDB base depreciation) | PV(10%,3,-28125) | ||
4 | 25,000 | 1,00,000 | (e-f) | 63,281 | 21,094 | VDB(200,000,0,8Year,year 3,Year 4,2) | (g-h) | $66,864 | PV(10%,Year3,-VDB base depreciation) | PV(10%,4,-21094) | ||
5 | 25,000 | 75,000 | (e-f) | 47,461 | 15,820 | VDB(200,000,0,8Year,year 4,Year 5,2) | (g-h) | $59,971 | PV(10%,Year4,-VDB base depreciation) | PV(10%,5,-15820) | ||
6 | 25,000 | 50,000 | (e-f) | 31,641 | 15,820 | VDB(200,000,0,8Year,year 5,Year 6,2) | (g-h) | $68,902 | PV(10%,Year5,-VDB base depreciation) | PV(10%,6,-15820) | ||
7 | 25,000 | 25,000 | (e-f) | 15,820 | 15,820 | VDB(200,000,0,8Year,year 6,Year 7,2) | (g-h) | $77,020 | PV(10%,Year6,-VDB base depreciation) | PV(10%,7,-15820) | ||
8 | 25,000 | - | (e-f) | - | 15,820 | VDB(200,000,0,8Year,year 7,Year 8,2) | (g-h) | $84,400 | PV(10%,Year7,-VDB base depreciation) | PV(10%,8,-15820) | ||
Total | 2,00,000 | $5,37,637 |
2. Henry has an assignment from his boss at Czech Glass and Wood Sculpting to evaluate...
1. For a country that allows switching depreciation methods between declining balance (not DDB) and straight line, determine the difference in depreciation for year 2 between the two methods and determine if a switch is advisable, according to the general rules of switching. The asset has a first cost of $100,000, a 5-year recovery period, a $10,000 salvage value, and d = 1/n. Fill in the table below (actual values) to visualize your determination. DB Model SL Model Yeart SD...