5)
use:
pOH = -log [OH-]
= -log (5*10^-2)
= 1.301
use:
PH = 14 - pOH
= 14 - 1.301
= 12.699
Answer: 12.70
6)
use:
pH = -log [H+]
2.78 = -log [H+]
[H+] = 1.66*10^-3 M
HA dissociates as:
HA -----> H+ + A-
4.5*10^-2 0 0
4.5*10^-2-x x x
Ka = [H+][A-]/[HA]
Ka = x*x/(c-x)
Ka = 1.66*10^-3*1.66*10^-3/(0.045-1.66*10^-3)
Ka = 6.355*10^-5
use:
pKa = -log Ka
= -log (6.355*10^-5)
= 4.1969
Answer: 4.20
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