Question

For the following reaction, 4.54 grams of water are mixed with excess zinc oxide . The...

For the following reaction, 4.54 grams of water are mixed with excess zinc oxide . The reaction yields 23.8 grams of zinc hydroxide .


zinc oxide(s) + water(l) ebab9d75-6e9a-4c80-9bcd-b491b668f097.gifzinc hydroxide(aq)

What is the ideal yield of zinc hydroxide? grams
What is the percent yield for this reaction?
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Answer #1

Zn(OH)2 (aq) zno (s) + H₂O(1) mase of H2O = 4.54g molar mass = 18.01 g/mol . moles of H₂O = 4.54 mol 18.01 TODO 0.25208 mol =

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