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A survey was taken of U.S. companies that do business with firms in India. One of...

A survey was taken of U.S. companies that do business with firms in India. One of the questions on the survey was: Approximately how many years has your company been trading with firms in India? A random sample of 44 responses to this question yielded a mean of 10.455 years. Suppose the population standard deviation is 7.7 years and the confidence level is 90% :

  1. What is the point estimate?                  
  2. What is the margin of error?                  
  3. Develop interval estimation for the mean number of years that a US company has been trading in India
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Answer #1

A) The point estimate is ar x = 10.455

B) At 90% confidence interval the critical value is z0.05 = 1.645

Margin of error = z0.05 * sigma/sqrt n

= 1.645 * 7.7/V44

= 1.9095

C) The 90% confidence interval for population mean is

ar x +/- ME

= 10.455 +/- 1.9095

= 8.5455, 12.3645

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