Homework Answers
a) Density = 2165 kg/m3
Thus, one m3 is 2165kg= 2165000g.
Molecular weight of NaCl= 58.44.
Thus, 58.44g of NaCl has Na number of Na atoms, thats 6.023*1023 Na atoms.(Where Na= Avogadro number)
Thus, 2165000g of NaCl has (2165*103 * 6.023*1023)/(58.44) = 22.313 * 1027 Na Atoms per m3. (Ans)
b) One unit cell edge= 0.563 nm = 0.563*10-9 m
Unit cell volume = (0.563 * 10-9)3 = 0.178 * 10-27 m3
Thus, 0.178 * 10-27 m3 has 4 Na atoms.
Thus, 1 m3 has = 4/(0.178 * 10-27) = 22.41 * 1027 Na atoms per m3(Ans)
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Unit Cell Calculations Name
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