Hi,
NaCl crystallizes as an interpenetrated fcc packing of Na+ and Cl- ions.
Hence, edge length = 2*rcation + 2*ranion
=> Since interionic Na+--Cl- distance = rcation + ranion? = edge length / 2 = 5.638/2 = 2.819
Density of NaCl lattice will be: mass of all atoms in one unit cell / volume of unit cell
Since 1 unit cell of NaCl consists 4 Na+ and 4 Cl- ions,
mass of one unit cell = 4*23 + 4*35.5 = 234 atomic unit = 234*1.66*10-24 grams
Volume of 1 unit cell (since its a cubic lattice) = (edge length)3
= (5.638*10-8 cm)3 = 179.22*10-24 cm3
Hence the density will be = 234*1.66/179.22 g/cm3
= 2.167 g/cm3
reported value from literature = 2.165 g/cm3.
The value calculated here is <0.1 % away from the actual value !
3. X-ray diffraction studies show that the edge length of the unit cell in crystal- line...
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