1)
moles Al2S3 = 16.4 g / 150.1580772 g/mol = 0.10921823391 moles
moles H2O = 10.1 g / 18.01528 g/mol = 0.56063519412 moles
moles H2S produced = 0.56063519412 / 2 = 0.28031759706 moles
mass of H2S = 0.28031759706 mol x 34.08088 g/mol = 9.55347038736 g
Answer: Mass of H2S = 9.55 g
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2) PART-D:
Are you sure Part-D is following up of above question, i mean relates to mass of H2S??????
percent yield = (actual yield / theoretical yield) x 100%
percent yield = (186 g / 9.55 g) x 100% = 1947 %
Answer: percent yield = 1947 % ------------------> this is impossible in any reaction
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3) PART-B:
moles Ca(OH)2 = 330 g / 74.09268 g/mol = 4.4538812741 mol
energy absorbed = 4.4538812741 mol x 65.3 kJ = 291 kJ
energy absorbed =291 kJ
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