The minute hand of a church clock is twice as long as the hour hand. After...

Question

Question

Answer 1

Answer #1

Using the constant angular speed of the two hands in radians per minute ω_m = 2 π / 60 and ω_h = 2 π / 12 × 60

one get the time at which the speed difference is at a maximum θ_m − θ_h = π

( ω_m − ω_h ) t_max = π

which gives the required configuration of the clock hands 32 minutes 44 seconds after midnight.

Answer 2

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