A 1.0 L buffer solution has 0.15 mol L-'HCN and 0.60 mol L-1 KCN. The K,...

Question

Question

A 1.0 L buffer solution has 0.15 mol L-HCN and 0.60 mol L-1 KCN. The K, of HCN is 4.9 X 10-10. Which action will destroy the

Answer 1

Answer #1

Answer

D) Add 0.50mol KOH to the buffer

Explanation

A buffer solution is a combination of weak acid and its conjucate base or weak base and its conjucate acid

given buffer is combination of weak acid HCN and its conjucate base CN^-

If NaOH is added to this buffer , as a base NaOH react with HCN

HCN + OH^- ------> CN^- + H2O

1:1 molar reaction

Initial mole of HCN = 0.15mol

Initial mole of CN^- = 0.60 mol

moles of NaOH added = 0.50mol

0.15 moles of NaOH react with 0.15 moles of HCN to produce 0.15 moles of CN^-

So, addion of NaOH destroy the buffer by removing the combination of HCN/CN^-

Answer 2

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