Question

If 20. cal of heat is added to 10.0 g each of copper and mercury at 15 °C, what is the final temperature of each element? chapter 7 practice problem 7.16 why are they putting a 10 in the Q formula instead of the 20 cal shouldn't the 10.0 be considered the mass and the 20 cal of heat be the "Q" in the formula?

Answer 1

Amount I treat added to each element = 20 cal - 2ox u.194 J = 83.50T specific treat of mercury (Eng). = 0.1395 J/g °C specific treat of topper Eco) 0.355 Il gioc as per law , heat change for Hg © = m x x 4Т 70 73.68 J = log x 0.1395 3/9.0c xOT AT = 835 g 59.9°C | 0.13 5 x 50 51 T-15°C = 59.9857°C T= 74.9goc (far mercury) for cooper OF mx TeuxOT AT= Q3.50 – 21.735°C 0.305x10 T= 21.735 +15°C = 37.735°C Ta = 36.7400