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A chemical engineer is studying the following reaction: CH (9)+2H,S(9) CS,(9)+4H (9) At the temperature the engineer picks, t
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Answer #1

Kp = 2.1

A)

Qp = p(CS2)*p(H2)^4 / p(CH4)*p(H2S)^2

= (3.68*1.91^4)/(5.94*5.98^2)

= 0.23

Qp is less to kp

So, reaction will move to the right

CH4: decrease

H2S: decrease

CS2: increase

H2: increase

B)

Qp = p(CS2)*p(H2)^4 / p(CH4)*p(H2S)^2

= (3.62*1.65^4)/(6.00*6.11^2)

= 0.12

Qp is less to kp

So, reaction will move to the right

CH4: decrease

H2S: decrease

CS2: increase

H2: increase

C)

Qp = p(CS2)*p(H2)^4 / p(CH4)*p(H2S)^2

= (4.32*4.45^4)/(5.30*4.71^2)

= 14.4

Qp is greater than kp

So, reaction will move to the left

CH4: increase

H2S: increase

CS2: decrease

H2: decrease

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