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A chemical engineer is studying the following reaction: HCH,CO (0)+CH NH (aq) – CH, CO (q) + CH3NH (g) At the temperature the
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Answer #1

reaction vessel A.

Q = [CH3CO2-][CH3NH3+] / [HCH3CO2][CH3NH2]

Q = (0.52)(0.50) / (1.16)(1.06)

Q = 0.212

Q < Kc , So equilibrium shifts in forward direction.

[CH3CO2-] = increase

[CH3NH3+] = increase

[HCH3CO2] = decraese

[CH3NH2] = decrease

reaction vessel B.

Q = [CH3CO2-][CH3NH3+] / [HCH3CO2][CH3NH2]

Q = (0.69)(0.67) / (0.99)(0.89)

Q = 0.52

Q < Kc , So equilibrium shifts in forward direction.

[CH3CO2-] = increase

[CH3NH3+] = increase

[HCH3CO2] = decraese

[CH3NH2] = decrease

reaction vessel C.

Q = [CH3CO2-][CH3NH3+] / [HCH3CO2][CH3NH2]

Q = (1.32)(1.29) / (0.94)(0.81)

Q = 2.2

Q =  Kc , So reaction is at equilibrium.

[CH3CO2-] = no change

[CH3NH3+] = no change

[HCH3CO2] = no change

[CH3NH2] = no change

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