Question

Using an equilibrium constant to predict the direction of spontan.. A chem - gineer is studying the following reaction: HCN(aq)+NH3() CN (aq)+NH(aq) At the temperature the engineer picks, the equilibrium constant K for this reaction is 1.2 The engineer charges ("fills") four reaction vessels with hydrogen cyanide and ammonia, and lets the reaction begin. She then measures the composition of the mixture inside each vessel from time to time. Her first set of measurements are shown in the table below. Predict the changes in the compositions the engineer should expect next time she measures the compositions compound concentration expected change in concentration increase decrease O ne change) HCN 0.72 M To NH, ORM of increase I decrease (ne change) 0.79 M of increase decrease (ne change) ( change) 0.99 M 1 increase decrease 054M increase (ne change) 066 M increase decrease (no change) 0.59 M increase decrease (no change) 1 increase (no change) 0.74 M 0.94 M Tincrease (ne change) 1.06 M increase (ne change) 0.19 M (no change) decrease f increase (no change) 0.34 M increase decrease

Answer 1

Using an equilibrium constant to predict the direction of spontan.. A chem - gineer is studying the following reaction: HCN(aq)+NH (aq)– CN (aq)+NH (aq) At the temperature the engineer picks, the equilibrium constant K for this reaction is 1.2. The engineer charges ("fills") four reaction vessels with hydrogen cyanide and ammonia, and lets the reaction begin. She then measures the composition of the mixture inside each vessel from time to time. Her first set of measurements are shown in the table below. Predict the changes in the compositions the engineer should expect next time she measures the compositions compound concentration expected change in concentration increase o decrease ne change) HCN 0.72 M To NH, ORM Increase I decrease (no change) 0.79 M I decrease (ne change) of increase increase (no change) 0.99 M 054M increase (no change 066 M increase decrease (ne change) 0.59 M increase decrease (no change) (no change) 0.74 M t increase 0.94 M Tincrease the change) increase (ne change) 1.06 M (no change) 0.19 M of increase (no change) 0.34 M increase

CN (aq) + NHA cag) HCN (aq) + NH₃ caq) Kc = 1.2 Qc = [[N] [NH4+ CHCNJCNH) ] 0.7980.99 6-12x0.88 Qc= 1.2 Kc = Qc. Rc = 1.2 Kc = Qc Qc = 0.065 kc Qc mass of bariam acetate = 20og. moles of BaC6zH30), = 200 -0.783 255 Concentration = 0.783 -2.61 0.300 -2.61 Le 0.300 concentration = 2.61 mol/L