Question

The owner of a local golf course wants to estimate the difference between the average ages of males and females that play on the golf course. He samples a group of men and women and then uses the sample statistics to calculate a 99% confidence interval of (6.28, 21.77). This interval estimates the difference of (the average age of men - the average age of women). What can we conclude from this interval?

Question 8 options:

	1) We are 99% confident that the average age of all men who play at the course is greater than the average age of all women.
	2) We do not have enough information to make a conclusion.
	3) There is no significant difference between the average age of men and women that play at the course at 99% confidence.
	4) We are 99% confident that the difference between the two sample means falls within the interval.
	5) We are 99% confident that the average age of all women who play at the course is greater than the average age of men.

Answer 1

Solution:

Given:  A 99% confidence interval for the difference between the average ages of males and females that play on the golf course is: (6.28, 21.77).

Differences are taken as: the average age of men - the average age of women

If both limits of confidence interval are positive, then mean of Men is greater than mean of women.

Since a 99% confidence interval is ( 6.28 , 21.77) and both the limits are greater than null difference 0, there is sufficient evidence to conclude that: the average age of all men who play at the course is greater than the average age of all women.

Thus correct option is:

1) We are 99% confident that the average age of all men who play at the course is greater than the average age of all women.