Question

sn1: write the reactions for each of the secondary, tertiary, and aryl substrates

Chemicals and Solvents, Chemical Abstract Service (CAS): (1) 1-chlorobutane, (109-69-3] (2) 1-bromobutane, (109-65-9) (3) 2-chlorobutane, (78-86-4) (4) 2-bromobutane, (78-76-2] (5) 2-chloro-2-methylpropane, (507-20-0) (6) bromobenzene, (108-86-1) (7) 2-bromo-2-methylpropane, (507-19-7) (8) ethanol, [64-17-5)

Answer 1

You have given the SN1 reaction.so you must know that ether is form in this reaction.so, I will write down all the reaction.

all the reactions will be same besides reactant and product.

in short, we will substitute halide ion from reactant and , combine reactant with CH3CH2O grp from the side where halide is removed.

let me give you one simple mechanism for this.

Am. 1 AgNO3 in CH₃ CH₂OH, CH-CH-CH2CH3 ez-CH2-CH-O-CH-CH3 Bo 2-bromo butane 2-ethoxy butane Let's see mechanism: Let's take, . CH3-CH-CH2=CH2 = R , & CHzor - CH2 C3 - – R-Br 87 SN': R-Br Agt Nog Chc-ÖH Rt Nogt Agt Bois (S) - CH₂ - CH₂ + to R'-' → co → R-6-CH-CH3 + 4CH-DHz + Noz

You have asked the reaction for secondary , tertiary and aryl substance.

So secondary substances are 3 and 4

tertiary substance are 5 and 7.

aryl substance is no. 6.

Reactions for these substances are as follows:

- CH-CH- Ch Agnez / a con, 03-04-44-0-cheCHE ci 2-chloro butaire 2-ethoxybutene 3 Agnoz/ CHHOH CH3 Chy¢-ch Ic - - z- & -o-ch-CH₂ test-butyl ethyl ether 3 2-chloso 2-methyl propune 04 ) AgNO₃ / - SHOH CH3-CH-CH₂-CH3 CH-CH - CH-0-CH-CH3 . B7 2-bromo butane 2-ethoxy butane AgNO₃ / GMSOM o-cz-CH3 ] ethyl phenyl ether bromo benzene - CT CH3 CH3 ao AgNO₃ / GMGOH - BO ap-¢-o-che-CH3 tert-butyl ethyl ether a-bromo 2-methyl propune

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