Question

Use SPSS and work the difference of two means problem Your task is to determine if Weight Lifters of Group B have more weight


→ T-Test Group Statistics Std Error Mean N Weightlifters Groups Group A Group B Mean 2.170 2.460 10 10 Std Devon 3335 4402 10


The Six-Step Plan 1. Declaration of the Null Hypothesis II. Declaration of the Alternate Hypothesis, M. Calculation of the Cr
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Answer #1

1) Null hypothesis:

H0: Mean of weight lifter GROUP A = GROUP B

2) Alternative Hypothesis:

H1: Mean of Weight of GROUP B> GROUP A

Here we conduct the one-tailed test because it depends on the alternative hypothesis our alternative hypothesis is one-sided GROUP B>GROUP A.

SPSS output

— Т-Test [DataSet0 Group Statistics Std. Error Mean Std. Deviation Mean group 3335 weight 10 2.170 1055 group a 10 2.460 4402

3)Calculation of the critical value

here we have two independent samples n1 & n2 so for two sample degree of freedom is n1+n2-2=10+10-2=18

so for using t table for 0.05 significance level critical value is 1.734

4)Calculation of test statistic

s2p = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22) = ((9/18) * 0.11) + ((9/18) * 0.19) = 0.15

s2M1 = s2p/N1 = 0.15/10 = 0.02
s2M2 = s2p/N2 = 0.15/10 = 0.02

t = (M1 - M2)/√(s2M1 + s2M2) = -0.29/√0.03 = -1.66

also, spss gives test statistic value t=-1.66

5)Statistical decision:

Here p-value 0.354>0.05 so we accept null hypothesis so there is no statistical difference between this group

6)statistical decision

weight lifter of group A and weight lifter of group B are the same



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