1) Null hypothesis:
H0: Mean of weight lifter GROUP A = GROUP B
2) Alternative Hypothesis:
H1: Mean of Weight of GROUP B> GROUP A
Here we conduct the one-tailed test because it depends on the alternative hypothesis our alternative hypothesis is one-sided GROUP B>GROUP A.
SPSS output
3)Calculation of the critical value
here we have two independent samples n1 & n2 so for two sample degree of freedom is n1+n2-2=10+10-2=18
so for using t table for 0.05 significance level critical value is 1.734
4)Calculation of test statistic
s2p =
((df1/(df1 +
df2)) * s21) +
((df2/(df2 +
df2)) * s22) =
((9/18) * 0.11) + ((9/18) * 0.19) = 0.15
s2M1 =
s2p/N1
= 0.15/10 = 0.02
s2M2 =
s2p/N2
= 0.15/10 = 0.02
t = (M1 -
M2)/√(s2M1
+ s2M2) =
-0.29/√0.03 = -1.66
also, spss gives test statistic value t=-1.66
5)Statistical decision:
Here p-value 0.354>0.05 so we accept null hypothesis so there is no statistical difference between this group
6)statistical decision
weight lifter of group A and weight lifter of group B are the same
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