Cost of machine 10 years from now is 100,000
A10 = 100,000
A10 = P( 1+ r) 10
r = 0.08
100,000 = P ( 1+ 0.08)10
P = 100,000 / ( 1.08)10
Cost of machine 10 years from now is A20
A20 = P( 1+r)20
A20 = [ 100,000 / ( 1.08)10 ]* ( 1+ 0.08)20
A20 = 100,000*(1.08)10
A20 = 215,892.5 = 215,900 ( closest answer)
Ans is b) $215,900
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