1 molecule of C20H42S3O2 contains 2 atoms of oxygen.
Hence, number of atoms in 30 molecules = 30 molecules * 2 atoms/1 molecules = 60 atoms
Hence, there are 60 oxygen atoms in 30 molecules of C20H42S3O2
Correct answer is Option C
Note - Post any doubts/queries in comments section.
Question 3 (1 point) oxygen atoms in 30 molecules of C20H42S3O There are A) 1.2 x...
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1. Choose the correct answer(s) to complete the following statement: One mole of oxygen (O2) gas is equivalent to _____________________. I. 6.022 × 1023 molecules of oxygen II. 6.022 × 1023 atoms of oxygen III. one mole of oxygen atoms IV. two moles of oxygen atoms 2. 50.0 g of Cl2 contains ________ mol Cl2. a. 0.705 b.1.41 c. 4.24 × 1023 d. 1775 e. 50.0 3. The number of grams in 0.350 mol of Na is a. 11.0. b....
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C 1.0 4 points hydrogen atoms in 25 molecules of C.H.S. QUESTION 10 There are c25 C 3.8 x 1024 c 100 6.0 x 10 1.5 x 10 un in the presence of excess oxygen yields
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Question 19 (1 point) How many molecules of CH4 are in 48.2 g of this compound? OA) 2.00 x 1023 OB) 1.81 x 1024 C) 5.00 10-24 D) 4.00 E) 4.64 x 1026
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