3. According to the Le Chatelier's principle, if a system at equilibrium is subjected to a stress (like change in concentration/pressure of reactants/products, temperature etc.) then it will move in a direction so as to offset the change to restore the equilibrium.
a. If more B(g) is added, then as B is a reactant and we are essentially increasing the concentration of reactant B, so the system will move in forward direction to reduce the amount of B(g) resulting in an increase in amount of C(g) at equilibrium.
b. A catalyst increases the rate of both forward and backward reaction to the same extent, so if we add a catalyst to the system, it will have no effect on the final equilibrium amount of C(g).
c. Concentration is given as amount of a substance per unit volume. So an increase in volume means a decrease in concentration. It also means a decrease in partial pressures of reactants and products. Thus an increase in volume always makes the reaction move to the side where there are number of moles of gas.
If the mixture is transferred to a reaction vessel of greater volume, it will move to backward direction (as there are 1+2=3 moles of gas on reactant side) resulting in a decrease in amount of C(g) at equilibrium.
d. If C(g) is removed, this means a decrease in concentration of product, so the system will move in forward direction to offset the decrease by producing more of C. So this will increase the amount of C(g) at equilibrium.
e. An inert gas added at a constant volume has no effect on equilibrium as though it increases the total pressure of the system, but it doesn't affect the partial pressure of reactants and products. So this doesn't affect the amount of C(g) at final equilibrium.
f. As enthalpy change
, i.e. the reaction is exothermic (as the sign of enthalpy change
is negative), so if we lower the temperature to 250 K, the reaction
will move in forward direction so as to offset the decrease in
temperature, resulting in production of heat and thus it moves in
direction of product C(g). So the amount of C(g) will be more at
the final equilibrium.
g. As A(g) is in excess, removing a small amount of A(g) has no effect on equilibrium and hence on amount of C(g) at equilibrium.
3. (15 Points, due Thurs 07 Nov) For the following reaction: A(s)+2B(8) = C(g), Kp <<1.0...
2. (10 points, due Thurs 07 Nov) What is the value of Kp at 298 K for the reaction C4H6 1/2 CH3OH1/2 CO +C4H8 given the following equilibrium data at 298K? (Note all reactions are in the gas phase. Hint: can you manipulate the reactions given below algebraically and add them together to obtain the reaction given above? How then should the Kp s of the reactions below be manipulated?) CH3OH CO + 2H2, Kp = 4.02 x 105 C4H6...
ALL problems must be submitted as an email attachment. 1. (15 points, due Th 07 Nov) Given that the reaction CO(g) + 2H2(g) = CHOH(g) has a Kp value of 0.00581 at 227°C, determine the Kc value for the following reaction at 227°C: 3CH3OH(g) =3CO(g) + 6H2 (8)
7 Consider the following reaction at 298 K: NH3(g) +HCI(g)NH4CI(s) Using the thermochemical data at 298 K given below (a) Determine the AH for the reaction. (2 marks) (b) Determine the AG for the reaction and comment on its value. (3 marks) (c) Determine the maximum work done available in the reaction. (3 marks) An equilibrium mixture, consisting of 0.5 atm of NHy(), 0.5 atm of HCKg) and excessive of NH Cl(s), is enclosed in a container at 298 K...
Consider the following reaction: A(g)⇌2B(g) Find the equilibrium partial pressures of A and Bfor each of the following different values of Kp. Assume that the initial partial pressure of B in each case is 1.0 atm and that the initial partial pressure of A is 0.0 atm. Make any appropriate simplifying assumptions. A.)Kp= 2.0 B.) Kp= 1.6×10−4 C.)Kp= 1.4×105
The equilibrium constant, Kp, for the following reaction is 0.110 at 298 K. NH4HS(s) NH3(g) + H2S(g) If ΔH° for this reaction is 92.7 kJ, what is the value of Kp at 212 K? Kp =
A-The following reaction has a Kp=1.6 x 104 at 1500 K. CH4(g) + Cl2(g) CH3Cl(g) + HCl(g) a. In a reaction mixture, PCH4 = 0.13atm , PCl2 = 0.035atm , PCH3Cl = 0.24atm , and PHCl = 0.47atm . Is the system at equilibrium? If not how does the reaction proceed to reach equilibrium? At equilibrium, the following stresses are applied. How is the equilibrium affected? Explain. i. HCl is removed. ii. CH3Cl is added iii. The volume is reduced...
Write the expressions for Kp for the following reactions: 1. a) 2NH3(g) + Co2(g) N2CH40(s) + H20 (I) b) CuO (s) + H2(g) Cu(l)+H20 (g) 2. At room temperature, a 1.5 L flask contains 3.0 moles of Cl, 0.5 mole of NOCI, and 4.0x10 mole of NO. Calculate Ke at this temperature for the following reaction: 2NO (g) + Cl2(g) 2NOCİ (g) 0.00245 M, does this represent a system at M, [No] 0.2 M and [Ch] If [NOCI] 2.0x 10...
6. (8 points, 2 points each) Consider the following reaction: CO2(g) + 2 NH3(g) = CO(NH2)2(s) + H2O(g) AH° = -90 kJ Circle the change expected for each of the following to reestablish equilibrium: a. Add CO2 to the equilibrium mixture form more form more no change products reactants b. Compress the equilibrium mixture at constant temperature. (smaller volume) form more form more no change products reactants c. Heat the equilibrium mixture form more form more no change products reactants...
(a) Consider the following reaction NH4HS(S) NH3g) H2S(g) For this reaction Kp 0.05 atm2 at 20 C. In a particular experiment, 0.06 mole of solid NH4HS is introduced into a 2.4 dm3 flask at 20 'C. Assume that the gases are ideal. Given: R 0.082 atm dm3 K-1 mol-1: R 8.314J K-1 mol-1 (i) Calculate the percent of the solid that will have decomposed at equilibrium (ii)Calculate the number of moles of ammonia that would have to be added to...
The equilibrium constant, Kp, for the following reaction is 0.110 at 298 K: NH4HS(s) ->NH3(g) + H2S(g) Calculate the partial pressure of each gas and the total pressure at equilibrium when 0.581 moles of NH4HS(s) is introduced into a 1.00 L vessel at 298 K. Assume that the volume occupied by the solid is negligible. PNH3 = atm PH2S = atm Ptotal = atm