Question

R-1.22 m, Q-1.85x10 c,a-q and-, Caloulate the 3 total force on Q Enter your response as positive if the force is to the right and negative if the force is to the left.
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Answer #1

Q3 Q2 01 F12 F23

SO,

Fnet = - 9e9*1.85e-6*1.85e-6 / 1.222 - 9e9*1.85e-6*1.85e-6 / 1.222

Fnet = - 0.020695 - 0.020695

Fnet = -0.04139 N

the net force is directed to the left.

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