Question

Please solve both with showing steps

5.29. A 4.0-cm diameter nozzle delivers a jet of water that strikes a flat plate normally. If the water speed is 50.0 m/s, calculate the force acting on the plate if (a) the plate is stationary.

Answer 1

5-29 diameter nozzle = d = 4 cm = 0 0.04 cm Area = pi/4 (d)^2 = pi/4 (4 times 10^-2) = 1.256 times 10^-3 m^2 velocity = v = 50 m/sec Force = Pav^2 P = density of water = 100 kg/m^3 = 1000 times 1.256 times 10^-3 times (50)^2 = 3140 N \r\n 5.32 P_2 = 0 (Exit atmospheric pressure) diameter of nozzle = 4 in d = 0.1016 m diameter of pipe = 10 in D = 0.254 m neglected head lossed i. e h_L = 0 Force on the pipe line = F = P_1 times Area of pipe F = 20 times pi/4 (10)^2 = 1570 p