Question

a For the following solution, calculate the normality: 28.7 mL of 0.173 M HCl diluted with water to a total volume of 78.1 mL Normality = b For the following solutiola calculate the normality: 0.179 M H3PO4 Normality = For the following solution, calculate the normality 0.00278 M Ca(OH). Normality = Submit Answer Try Another Version 10 item attempts remaining

Answer 1

a)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 0.173 M

V1 = 28.7 mL

V2 = 78.1 mL

use:

M1*V1 = M2*V2

M2 = (M1*V1)/V2

M2 = (0.173*28.7)/78.1

M2 = 0.0636 M

Answer: 0.0636 M

b)

1 H3PO4 has 3 ionisable H+

So,

Normality =3* Molarity

= 3*0.179 N

= 0.537 N

Answer: 0.537 N

c)

1 Ca(OH)2 has 2 ionisable OH-

So,

Normality =2* Molarity

= 2*0.00278 N

= 0.00556 N

Answer: 0.00556 N