Question

I Review PartA A spaceship maneuvering near Planet Zeta is located at What is the spaceship's position when the engine shuts off? Give your answer as a vector measured in km. (600i 400j 200k) x 103 km, relative to the planet, and traveling at v 9500i m/s. It turns on its thruster engine and accelerates with i-(40i-20k) m/s2 for 35 min. Express your answer in terms of the unit vectors i, j, and k. Use the 'unit vector button to denote unit vectors in your answer. r= x103 km Submit Request Answer Provide Feedback Next>

Answer 1

We will use simple kinematics with formula

S= ut+1/2at^2

Calculation will be as follows