Question

Molecules of I2 are produced by the reaction of 0.4442 mol of CuCl2 according to the following equation. 2 CuCl2 + 4 KI → 2 CuI + 4 KCl + I2 (a) How many molecules of I2 are produced? (b) What mass (in g) of I2 is produced?

Answer 1

let si be the number of molecules of I Produced by 0.4442 mol of ma a moles of cud, gives 0.4442 holes of Cull, gives 6.023x10 23 molecules of I. X Cross multiply - 23 9x = 6.023x 10²3 x 0.4442 23 X = 1.3377683X10 molecules of Is Produced by Let y be the mass 0.4442 mal of call a moles of rudy gives 0.4442 moles of cully gives - 253.8089 g Cyl Cross multiply 2y = 353.8089 x 0.4442 y = 56.37095669 9.