Question

An Olympic archer misses the bull's eye 14% of the time. Assume each shot is independent of the others. If she shoots 7 arrows, what is the probability of each of the results described in parts a through f below? c) Her first miss comes on the second or third arrow The probability is 0.2239 (Round to four decimal places as needed.) d) She misses the bull's-eye exactly 3 times. The probability is 0.0525. (Round to four decimal places as needed.) e) She misses the bull's-eye at least 3 times. The probability is (Round to four decimal places as needed.)

Answer 1

Here we have D = 0.14 qrip : 160.145086 nar (C) Pl first miss in and or 3ard) EPL binot miss in end) + Plfingt miss in 3rdy = 0.86*0.14 +10.84J** 0.14 = 0.1204 + 0.103549 = 0.223944 = 10:2239) Round to four decimal - Places (D) Pl x= 3) = ne pe lap) Max la Pl x-31-n x non (ba (from Binomial distribution) = 7C (0.143 (1-0.1897-3 = 0.05253 - 10.0525) Round to four duimal 23 3 places (C) Pl*33) = Į ne logre 11-M-X = "es 10.1999c9-0.1439+...+?0- 1aj"(1-0. 13° : 0.06196 - 10.0620 Round to four decimas - Places

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