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If 0.45 mol 2 0.45mol Cl2 and 2.92 mol la are added to a dol flask at 25°C. What is the molar con centration of Icl at equili
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Ang NOTĘ: I AM ASSUMING VALUES Guven QRES: number of moles: I = 0.95 mol of I number of moles of C = 0.95 mol number of moles2.922 X = 2.672 0.95 tu 2.92-8=21673 (0:95+x) 2.92 - X= 2.539 +216738 2.92-2.539 = (2,673+1)x x= 0.1037 20 [Ici lequelibri co

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