Suppose that a 2.00L glass flask is 0.500 mol of H2 and 0.500 mol Cl2 are...
Homework Answers
H2 + Cl2 
2HCl
| H2 | Cl2 | 2HCl | |
| Initial | 0.5/2 | 0.5/2 | 0 |
| Change | -x | -x | 2x |
| Equilibrium | 0.5/2-x | 0.5/2-x | 0.11 |
Keq = [HCl]2 /[H2][Cl2]
[HCl] = 0.11 = 2x therefore ,x = 0.11/2 = 0.055
[H2] = 0.5/2 - 0.055 = 0.195
[Cl2] = 0.5/2 - 0.055 = 0.195
Keq = (0.055)2/(0.195)2 = 0.079
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