Question

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6. (a) Calculate the difference in energy, AE, between the n=3 and n 2 energy levels in a Bohr hydrogen atom. I (b) Calculate the wavelength (in nm) of the light emitted when an electron drops from the n=3 to the n 2 energy level of a Bohr hydrogen atom. 7) Of the following transitions in the Bohr hydrogen atom, the results in the absorption of the highest-energy photon. A) n 1-n= 6 B) n-3n-6 C) n 1n=4 transition D) n -3-n = 6 E) n-6-n-3

Answer 1

@ : JE - 2.18x1618 Şý - ?- 2018x1518x5 - 36 Joule & - -0.30278 10 8 DE = 0.3027x1018 Joule she speed of light = 0.3027 X108 wavelength of Photon 6.62x1634x3x1080.3027 x 1018 Planck's Constant to 65.609 x 10 8 meters - 656 nom ļ Silom = 109m? © As we know that energy & I where his shell member So é boesent in shell closer to Buceous have highest energy and as we move farther away from nucleous energy wood will decreases So maxth value of DE for n=1 to n = 6 (A)