Question

please Q b, Q C , Q D,

Experiment 4: Limiting reagent 45 information for step by step directions for using Excel. Att your lab report. ons for using Excel. Attach a copy of your graphs to 4. Answer the following questions about the graphs you just made. a. Is the slope of each reactant positive or negative? Explain why you observe If the slope is produchey will be cather po reactant positiul means it ineresly oneta is aces- b. Is the slope of the product positive or negative? Explain why you observe this trend. c. Which reactant determines the total number of NH, molecules you can produce? How do you know? What term is used to designate this type of reactant? d. Which reactant is present in excess? How do you know? 5. Now consider the molar interpretation of the balanced chemical equation and complete the table below: 3H2(g) N; (g) + 2NH, (s) + # of Rxn of moles of H: # of moles of N; # of moles of NH3 events (moles) remaining remaining produced 1.8 - 0 0.4 3.6 0.8 2.4 1.2 1.2 0.6 2. 1.6 3.2 0.2 3.2 6. Using Excel and the values in the table above, graph the number of reaction events (x axis) vs number of reactant moles (y axis). Make one graph for each reactant. Graph the number of reaction events (x axis) vs number of product moles (y axis). You will be creating a total of three graphs on ONE set of axes. Please see supplemental information for step by step directions for using Excel. Attach a copy of your graphs to your lab report. 7. Answer the following questions based on the graphs you just generated. 2. How do graphs generated based on a molecular interpretation (question 2) and the molar interpretation (question 5) compare? If trends are similar explain why. If trends vary explain why. There are no diffenents, the only thy chengly is scally

Answer 1

3H₂(g) + Nalg) 4.8 1.8 2NH2(g) 0 mols y Ams.b) slope of puiduel s slope of product will be positive as the concentration of puoclukt is añerenong with time . For an increasing curre , scope is positive And e) Imole z reacts with 3 mol H₂ Here 1.8 molų is present se loq Nol N, will react with → 18x3 mol of the 5.4 mol of the But in reaction only to8 mol of H₂ are present . mians this will leve fully covsumid. Hy will determine the total number of NHz molecules . Po hus Hy is the limiting reagent. And a From above calculations it can be seen that the will be consumed fully, as moles of the to react with Nz are less, so Nz will remain in exuss.. idence Na will be present in excess. IGS Scanned with 2.ÇamScanner