Here first of all use Photo equation given by Einstein:
According to this equation if Light if energy E (more than work function of metal) is incident on the surface of metal then electrons get ejected and move with Kinetic energy KE
Equation is given by
E = W + KE
When an electron move perpendicular to the uniform magnetic field then force on electron due to magnetic field given by Bev provides the centripetal force to the electron so that electron traces a circle of radius R given by R = mv/ Be
from this equation we can calculate the velocity needed to trace the given radius. Putting this velocity value into the photo equation the wavelength of radiation by which the metal surface is to be irradiated can be calculated.
Here i have attached a scanned sheet for the detail solution.
Problem4 The work function of chosen metal W 1,5 eV. What is a wavelength A of...
The photoelectric work function energy for gold metal is 4.82 eV
(per electron). What wavelength of radiation must be directed at
the surface of gold metal in order to eject electrons electrons
having a maximum kinetic energy of 3.20×10 –20 Joules/electron.
[Note: The electron volt (eV) is a common energy unit for work
function energies. 1 eV = 1.602×10 –19 Joules.]
-20 The photoelectric work function energy for gold metal is 4.82 eV (per electron). What wavelength of radiation must...
1) Light of wavelength 310nm is shined on a metal with work function = 1 eV. What will be the maximum kinetic energy of the emitted electrons? 2) Light is shined on a metal with work function 2.0 eV, and electrons are emitted creating a photocurrent. When a decelerating voltage of magnitude 1.0 V is applied, the current goes to zero (i.e. the magnitude of the stopping voltage is 1V). What is the wavelength (in nm) of the incoming light?...
Sodium metal has a work function of 2.28 eV. (a) At what wavelength of incident light will electrons be ejected from the material? (b) If light of wavelength 450 nm is incident on the sodium, determine the maximum kinetic energy of the ejected electrons 13.4
The photoelectric work function energy for manganese metal is 3.76 eV (per electron). What wavelength of radiation must be directed at the surface of manganese metal in order to eject electrons electrons having a maximum kinetic energy of 2.00×10 –19 Joules/electron. [Note: The electron volt (eV) is a common energy unit for work function energies. 1 eV = 1.602×10 –19 Joules.] Wavelength (λ) = Answer nm
When ultraviolet light with a wavelength of 280 nm is incident on a particular metal surface, electrons are emitted via the photoelectric effect. The maximum kinetic energy of these electrons is 1.44 eV. (a) What is the work function of the metal? eV (b) What is the threshold frequency for this particular metal? Hz
When UV light of wavelength 288 nm falls on a metal surface, the maximum kinetic energy of emitted electrons is 1.66 eV What is the work function of the metal?
The photoelectric work function energy for manganese metal is 3.76 eV (per electron). What wavelength of radiation must be directed at the surface of manganese metal in order to eject electrons electrons having a maximum kinetic energy of 2.00×10 –19 Joules/electron. [Note: The electron volt (eV) is a common energy unit for work function energies. 1 eV = 1.602×10 –19 Joules.]
The photoelectric work function energy for manganese metal is 3.76 eV (per electron). What wavelength of radiation must be directed at the surface of manganese metal in order to eject electrons electrons having a maximum kinetic energy of 2.00×10 –19 Joules/electron. [Note: The electron volt (eV) is a common energy unit for work function energies. 1 eV = 1.602×10 –19 Joules.]
When UV light of wavelength 245 nm falls on a metal surface, the maximum kinetic energy of emitted electrons is 1.40 eV . Part A What is the work function of the metal?
The work function of a certain metal is φ = 3.05 eV. Determine the minimum frequency of light f0 for which photoelectrons are emitted from the metal. (Planck's constant is: h = 4.1357×10-15 eVs.) Determine the corresponding wavelength of light. (Possibly useful constant: hc = 1240 eVnm.) Calculate the kinetic energy of the emitted electrons if the frequency of the photons is doubled to 2f0.