Question

I need help figuring these calculations out

Mental Data Reagents ass of weighing Boat/Paper Trial Trial 2 Mass of Weighing Weighing Boat/Paper and Ba(NO3)2 31 Mass of Ba(NO3)2 Mass of weighing Boat/Paper 55 of Weighing Boat/Paper and NH,SO. HT 2.493 Mass of NH SO,H Precipitate Trial 1 Trial 2 Mass of Filter Paper 0.446 Mass of Filter Paper and Precipitate Mass of Precipitate Mass Ratio Average Mass Ratio? "Precipiate must be room temperature before the moss is determined. Use the mass ratio from trial 1 if a second trial is not completed Group No. Student Names Average Mass Ratio 1 Amma & Yeming 0.0483 2 T Travis t Chris I o.1967 Jacob & Nicole o.l4o5 Andrea & Mackenzie ! 0.6456 Erin & Trinity 0.320 0.15 Shannon & Radiboul 0.8996

Answer 1

1. mean = total value/ N

mean =( 0.0483+0.1947+0.1405+0.6456+0.3201+0.115+0.8996)/7

= 0.337

2. to calculate standard deviation, first calculate the mean of the number = 0.337

then, substract mean value with from each number

(0.337-0.0483)=0.2887= 0.2887^2= 0.08334

(0.337-0.1947)=0.1423=0.1423^2=0.0202

(0.337-0.1405)=0.1965=0.1965^2=0.0386

(0.337-0.6456)=-0.3086=-0.3086^2=0.0952

(0.337-0.3201)=0.0169=0.0169^2=0.00028

(0.337-0.115)=0.222=0.222^2= 0.0492

(0.337-0.8996)=-0.5626=-0.5626^2=0.316

then square up of all the differences and add square of all the differences = 0.5541

Then divide this number with numbers of number minus one. Here, we have 7 total numbers. The above number (sum of differences) is divided by (7-1 = 6)

That is, (0.5541/6) = 0.092356

Final step is finding the standard deviation is the square root of the above obtained number.

That is (0.092356)^(1/2) = 0.3039

Hence, the standard deviation is = 0.3039