What I have so far for data etc. My question I need help with though is:...
answer the question based on data available for each trial
Table I. Gravimetric and Titration Data for the Determination of Ba(OH). Concentration Trial 1 Trial 2 Trial 3 Volume at Equivalence Point (mL) 7.857 10.867 8.821 Mass of filter paper + precipitate (g) 0.4171 0.8905 0.8724 Mass of filter paper (g) 0.2577 0.6387 0.6294 Mass of precipitate (g) Molarity if HSO (M) 0.100 0.100 0.100 Moles of H.SO, used to reach equivalence point Average M Molarity of Ba(OH) (titration) d...
Please show all work !
Experiment 9 Conductometric Titration and Gravimetric Determination of a Precipitate REPORT SHEET Name: DATA TABLE Trial 1 Trial 2 Trial 3 Equivalence point (mL) 27.l16 mL Mass of filter paper precipitate ()311 I1133 20139 03228 Mass of filter paper (9) Mass of precipitate (g) Molarity of HaSO (M) DATA ANALYSIS (If you need more space, provide your answers on the back page) 1. Use the titration results to calculate the moles of H2SO4 that were...
Name Section Date Lab Partner PRE-LAB ASSIGNMENT: CONDUCTIMETRIC TITRATION AND GRAVIMETRIC DETERMINATION OF A PRECIPITATE (Show work for All Problems) 1. Define the analyte and titrant in this experiment. How can you differentiate between them? 2. The following data below was gathered during a conductimetric titration involvinga standard solution of 0.100 M sulfuric acid, H.,SO, and 20.0 mL of barium hydroxide, Ba(OUsing LoggerPro, plot these data, perform a linear regression (refer to the Data Analysis section), and answer the questions...
What is the theoretical yield of H2SO4 + BaCl2 ---> BaSO4 +
2HCl
Given data:
Concentration of BaCl2 = 0.20 M
Concentration of H2SO4 = 6 M
volume of H2S04 = 5.00 mL
What is the theoretical expected yield of precipitate as
calculated using stoichiometry?
Compare actual yield and theoretical yield. Calculate percent
yield.
Data:
Trial 1: Mass of BaSO4 precipitate = 0.191 g
Trial 2: Mass of BaSO4 precipitate = 0.187 g
What is the Millimoles of BaSO4 for...
Hey, i need help with the data analysis part of my HW. Thank
You!
Mass of beaker (e) Trial I Trial 2 2 Mass of beaker and salt mixture (g) Mass of salt mixture (g) O63.9 1.2325 4 Mass of filter paper (e) 1,239 Mass of filter paper and product after air-dried oroven-dried (g) 1.S149 6Mass of dried product (g) 0.2824 252 CalaD,0 1. Formula of dried product CaCaOnHyO 0.2929 B. Determination of Limiting Reactant L. Limiting reactant in salt...
I need help plotting the mass of precipitate versus moles of
Pb(NO3)2 .
Reaction Equation: Pb(NO3)2 + 2KBr →
PbBr2 + 2KNO3
Volume (mL) Solution Mixture 0.50 M Pb(NO3)2 0.50 M KBT 2.00 18.00 4.00 16.00 6.00 14.00 8.00 12.00 10.00 10.00 12.00 8.00 14.00 6.00 16.00 4.00 18.00 2.00 Data Collection | Experimental Data Assignment Number Volume Pb(NO3)2 16m Moles Pb(NO3)2 Volume KBr 114 mL Moles KBT Mass of watchglass and filer paper (g) 28.7455 | 1st heating: Mass...
I need help figuring these calculations out
Mental Data Reagents ass of weighing Boat/Paper Trial Trial 2 Mass of Weighing Weighing Boat/Paper and Ba(NO3)2 31 Mass of Ba(NO3)2 Mass of weighing Boat/Paper 55 of Weighing Boat/Paper and NH,SO. HT 2.493 Mass of NH SO,H Precipitate Trial 1 Trial 2 Mass of Filter Paper 0.446 Mass of Filter Paper and Precipitate Mass of Precipitate Mass Ratio Average Mass Ratio? "Precipiate must be room temperature before the moss is determined. Use the...
Data and Observations I. Determining the Unknown Acid Sample Size CvOt0ni aid identification code of unknown weak acid concentration of NaOH solution, M mass of weighing paper plus unknown acid, g mass of weighing paper, g final buret reading, mL initial buret reading, mL 2.0506M 2.0 Ill. Titrating the Unknown Acid identification code of unknown weak acid concentration of NaOH solution, M 500M determination 1 determination 2 LGS G mass of weighing paper plus unknown acid, g mass of weighing...
Please help!! with question (18
,19, 20 )
the data is coming directly from
professor and i think she made a mistake because after I work out
problem I get theoritcal yeild of 0.850 grams
CaCO3 but the experiment actual yield is 8.322 grams (work out
question 12 )
Carbonate LI General Chemistry Lab I H.Y. & S.D. ame ata Sheet Section Date • Precipitating Cacos 1) Volume of Na2CO3, mL 8.22mL or 0.00824 2) Molarity of Na2CO3 solution, mol/L...
i added a,b,c just incase you need it
i just need help with d-f
A student prepared 7.2 g of Co,(NH3),Cl . She then analyzed the compound to find the values of x, y, and z. In the gravimetric determination of chloride, she weighed out a 0.2988 g sample of the product compound and reacted it with AgNO3. The following data were obtained: Mass of crucible plus AgCl 19.0020 g Mass of crucible 18.4628 g a. Calculate the mass of...