Question

A standard stock solution of Cr6+ was prepared by dissolving 0.507 g dried K2CrO4 (formular mass=194.1896...

A standard stock solution of Cr6+ was prepared by dissolving 0.507 g dried K2CrO4 (formular mass=194.1896 g/mol) in deionized water and diluting to 100 mL in a volumetric flask. What is the concentration of the standard solution in units of g Cr/L? The molar mass of chromium is 51.9961 g/mol.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Moles of K2CrO4 = 0.507 gm / 194.1896 gm mol-1 = 0.0026 mol = mol of Cr+6

Concentration in gm / litre for Cr+6 = 0.0026 mol x ( 51.9961 gm / mol ) / ( 100 x 10–3 litre ) = 1.3518 gm / litre

Add a comment
Know the answer?
Add Answer to:
A standard stock solution of Cr6+ was prepared by dissolving 0.507 g dried K2CrO4 (formular mass=194.1896...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A stock solution was prepared by dissolving 0.593 g of pure ASA (molar mass = 180.2...

    A stock solution was prepared by dissolving 0.593 g of pure ASA (molar mass = 180.2 g/mol) with NaOH solution and diluting with water in a 1000 mL volumetric flask. This was followed by pipetting 4.00 mL of the stock solution into flask A and 5.0 mL of the stock into flask B. Flasks A and B were each diluted to 20 mL mark of the volumetric flask. What are the concentrations, in molarity, of ASA in flasks A and...

  • A Na_2CO_3 standard solution is prepared by transferring 2.4817 g of primary standard grade sodium carbonate...

    A Na_2CO_3 standard solution is prepared by transferring 2.4817 g of primary standard grade sodium carbonate into a 250.0 mL volumetric flask, dissolving the sample in ~ 100 mL of distilled deionized water, and diluting to the mark. A 25.00 mL aliquot is taken and titrated with 42.65 mL of HCI solution. Calculate the concentration of the HCI solution. (Molar masses are: Na_2CO_3 = 105.989 g/mole; HCI = 36.461 g/mole; H_2O = 18.015 g/mole.) Circle the best choice. (Showing calculations...

  • A stock solution was prepared by dissolving 0.593 g of pure ASA (molar mass = 180.2...

    A stock solution was prepared by dissolving 0.593 g of pure ASA (molar mass = 180.2 g/mol) with NaOH solution and diluting with water in a 1000 mL volumetric flask. This was followed by pipetting 4.00 mL of the stock solution into flask A and 5.0 mL of the stock into flask B. Flasks A and B were each diluted to 20 mL mark of the volumetric flask. What are the concentrations, in molarity, of ASA in flasks A and...

  • 3. a) A standard ZnCl2 solution is prepared by dissolving 0.6483 g of Zn in an...

    3. a) A standard ZnCl2 solution is prepared by dissolving 0.6483 g of Zn in an HCl solution and diluting to volume in a 1.00 L volumetric flask. An EDTA solution is standardized by titrating a 15.00 mL aliquot of the ZnCl2 solution, which requires 16.12 mL of EDTA solution to reach the end point. Determine the concentration of the EDTA solution. (2 pts)      b) A 1.5146 g sample of powdered milk is dissolved and the solution titrated with...

  • Determine the molarity of a solution of potassium chloride that is prepared by dissolving 1.4753 g...

    Determine the molarity of a solution of potassium chloride that is prepared by dissolving 1.4753 g of KCl in a 100-mL volumetric flask and filling it to the calibration mark with deionized water. Use a molar mass with at least 4 significant figures so that the number of SF in the calculated molarity is not limited. Show all calculations (including labeled conversion factors) and express the answer with the appropriate number of significant figures. According to the manufacturer, the volume...

  • A solution of sodium was prepared by dissolving 0.0309 g of NaCl in distilled deionized water...

    A solution of sodium was prepared by dissolving 0.0309 g of NaCl in distilled deionized water and brought up to the mark in a 200 mL volumetric flask. 10.0 mL of this solution was diluted to 250.0 mL. What is the concentration (ppm) of sodium the final solution

  • A stock solution of Cu2+(aq) was prepared by placing 0.9157 g of solid Cu(NO3)2∙2.5 H2O in...

    A stock solution of Cu2+(aq) was prepared by placing 0.9157 g of solid Cu(NO3)2∙2.5 H2O in a 100.0-mL volumetric flask and diluting to the mark with water. A standard solution was then prepared by transferring 2.00 mL of the stock solution to a second 25.00-mL volumetric flask and diluting to the mark. What is the concentration (in M) of Cu2+(aq)in the stock solution? What is the concentration (in M) of Cu2+(aq)in the standard solution?

  • 1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of...

    1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of 0.100 M NaCl. Solution A is prepared by pipeting 10 mL of the stock solution into a 250-mL volumetric flask and diluting to volume. Solution B is prepared by pipeting 25 mL of solution A into a 100-mL volumetric flask and diluting to volume. Solution C is prepared by pipeting 20 mL of solution B into a 500-mL volumetric flask and diluting to volume....

  • PLEASE HELP!! An EDTA solution was prepared by dissolving 2.611 g of purified and dried Na_2...

    PLEASE HELP!! An EDTA solution was prepared by dissolving 2.611 g of purified and dried Na_2 H_2 Y_2 middot 2H_2O in sufficient water to give 1.000 L. Calculate the molar concentration, given that the solute contained 0.3% excess moisture. Concentration =_______M

  • 2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water...

    2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water to make 150 mL of a stock solution. She then took 22.5 mL of the stock solution and diluted it with enough water to make 250. mL of a working solution. (5 pts. each) A. What is the molar concentration of NaOH in the stock solution? # of moles x 1000 Naot mass= 15,09 g molanty volume of source (m) Mol 40 g/mol voline...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT